ohmedfisika: Difraksi

$\bg_green \120dpi \inline \color{red}Difraksi\,\,pada\,\,Celah\,\,Tunggal\\\bullet d\,sin\,\theta=n\lambda \\\bullet d\frac{y}{L}=n\,\lambda \\\rightarrow n=1,2,3,...$

dengan

$\bg_green \100dpi \\d=lebar\,\,celah\,\,tunggal/celah\,\,sempit\\y=jarak\,\,pita\,\,gelap\,\,ke-n\,\,dari\,\,pusat\\L=jarak\,\,celah\,\,ke\,\,layar\\\theta =sudut\,\,simpang\,\,cahaya$

$\bg_green \120dpi \inline \color{red}Interferensi\,\,\,\,Celah\,\,Ganda\\\bullet Garis\,\,Terang\\d\,sin\,\theta=n\lambda \\ d\frac{y}{L}=n\,\lambda \\n=0,1,2,3,...\rightarrow n=0\,\,(terang\,\,pusat)\\\bullet Garis\,\,Gelap\\d\,sin\,\theta =(n+\frac{1}{2} )\lambda \\d\frac{y}{L}=(n+\frac{1}{2})\lambda \\n=0,1,2,3,...\rightarrow n=0\,\,(garis\,\,gelap\,\,ke\,\,1)$

$\bg_green \120dpi \inline \color{red}Kisi\,\,Difraksi\,\,\\\bullet Garis\,\,Terang\\d\,sin\,\theta=n\lambda \\ \frac{1}{N}\,\,sin\,\theta =n\,\lambda \\n=0,1,2,3,...\rightarrow n=0\,\,(terang\,\,terang\,\,pusat\\d=jarak\,\,antar\,\,kisi=tetapan\,\,kisi\\N=banyaknya\,\,kisi\,\,tiap\,\,satuan\,\,panjang$
$\bg_green \120dpi \inline \color{red}Daya\,\,Urai\\\bullet d_m=1,22\frac{\lambda \,L}{D}\\Sudut\,\,Resolusi\,\,Minimum\\\bullet \theta _m=1,22\frac{\lambda}{D}\\D=diameter\,\,bukaan\,\,alat\,\,optik\\L=jarak\,\,benda\,\,dari\,\,lensa\\\theta =sudut\,\,resolusi\,\,minimum\,(radian)\\d_m=daya\,\,urai\,(m)$

$\bg_green \120dpi \inline \color{red}Polarisasi\,\,Cahaya\\\bullet Sudut\,\,Polarisasi\\\theta_p+r=90^o\\tan\,\theta_p =\frac{n_2}{n_1}\\\theta_p =sudut\,\,datang\,\,yang\,\,menghasilkan\,\,sinar\,\,pantul\\yang\,\,terpolarisasi\,\,sempurna\\n_2=indeks\,\,bias\,\,bahan\\n_1=indeks\,\,bias\,\,medium\\\bullet Polaroid\\I_2=I_1\,cos^2\theta =\frac{1}{2}I_0\,cos^2\,\theta\\\theta = sudut\,\,antara\,\,analisator\,\,dan\,\,polarisator\\I_1=intensitas\,\,cahaya\,\,yang\,\,melewati\,\,polarisator\\I_2=intensitas\,\,cahaya\,\,yang\,\,melewati\,\,analisator$

ohmedfisika

Difraksi

Tidak ada komentar:

Posting Komentar